Series programs in C
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int main( ) { int n, i; printf("Enter Value for N : "); scanf("%d", &n); for(i=1; i<=n; i++) { printf("%d ", i); } printf("\n"); return 0; }OUTPUT :
Enter Value for N: 11 1 2 3 4 5 6 7 8 9 10 11
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#include<stdio.h> int main( ) { int n, i; printf("Enter Value for N : "); scanf("%d", &n); for(i=1; i<=n; i++) { if(n%2 == 0) { printf("%d ", i); } } printf("\n"); return 0; }OUTPUT :
Enter Value for N: 15 2 4 6 8 10 12 14
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#include<stdio.h> int main( ) { int n, i; printf("Enter Value for N : "); scanf("%d", &n); for(i=1; i<=n; i++) { if(n%2 != 0) { printf("%d ", i); } } printf("\n"); return 0; }OUTPUT :
Enter Value for N: 15 1 3 5 7 9 11 13 15
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#include<stdio.h> int main( ){ int n, i, value; printf("Enter Value for N : "); scanf("%d", &n); for(i=1; i<=n; i++) { value = i*3; printf("%d ", value); } printf("\n"); return 0; }OUTPUT :
Enter Value for N: 10 3 6 9 12 15 18 21 24 27 30
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#include<stdio.h> #include<math.h> int main( ) { int n, i, value=0; printf("Enter Value for N : "); scanf("%d", &n); for(i=0; i<=n; i++) { value = value + pow(2, i); printf("%d ", value); } printf("\n"); return 0; }OUTPUT :
Enter Value for N: 6 1 3 7 15 31 63
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#include<stdio.h > int main( ) { int i, j, factors; for(n=2; j<=20; n++) { factors = 0; for(i=1; i<=n ; i++) { if(n%i == 0) { factors++ } } if(factors == 2) { printf("%d ",n); } } return 0; }OUTPUT :
2 3 5 7 11 13 17 19
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#include<stdio.h> int main( ){ int i, a,b,c; printf("Enter Value for N : "); scanf("%d", &n); a = -1; b = 1; for(i=0; i < n; i++) { c = a+b; printf("%d ",c); a = b; b = c; } printf("\n"); return 0; }OUTPUT :
Enter Value for N : 8 0 1 1 2 3 5 8 13